Question

What is the average atomic mass of the following isotopic mixture - 42.10 g/mole- 93.50%; 48.30 g/mole 6.200%; 50.40 g/mole - 0.3000%? Show your work!!

Answer 1

40.03g/mole

Step-by-step explanation:

Given parameters:

Mass = 42.10 g/mole and abundance = 93.50%

Mass = 8.30 g/mole and abundance = 6.200%

Mass = 50.40 g/mole and abundace = 0.3000%

Find;

Average atomic mass = ?

Solution:

Average atomic mass = sum (mass x abundance)

Average atomic mass = (
`(93.50)/(100) x 42.1`) + (
`(6.2)/(100)` x 8.3) + (
`(0.3)/(100) x 50.4`)

= 39.36g/mole + 0.52g/mole + 0.15g/mole

= 40.03g/mole