Answer:
5705
Explanation:
The sum of an arithmetic series is the product of the number of terms and the average term. The average term is the average of the first and last terms.
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Here, the first term is 47, the last term is 116, and the number of terms is (116 -46) = 70. The common difference is 1. (The terms are consecutive integers.)
The sum is ...
sum = (70)(47 +116)/2 = 35(163) = 5705
The sum of the sequence is 5705.
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Alternate solution
The sum of n consecutive natural numbers is n(n+1)/2. The sum of the numbers 47 to 116 will be the sum of the first 116 natural numbers less the sum of the first 46.
sum = (116)(117)//2 -(46)(47)/2 = 6786 -1081 = 5705