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24 votes
24 votes
Find the slope of the line that contains (3, –2) and (4, 3).
Can someone help fast please?

User Trong
by
2.5k points

2 Answers

11 votes
11 votes

Answer:

5

Explanation:

M equals slope

M=3- -2/4-3

M=5/1

Therefore your slope would be 5

User Robroc
by
3.0k points
19 votes
19 votes

Answer:


\boxed {\boxed {\sf m=5}}

Explanation:

The slope of a line tells us the steepness and direction of a line. It is the change in y over the change in x (rise over run). It is calculated using the following formula:


m= (y_2-y_1)/(x_2-x_1)

In this formula, (x₁, y₁) and (x₂,y₂) are the coordinates the line passes through. The line contains (3, -2) and (4,3), therefore:

  • x₁ = 3
  • y₁ = -2
  • x₂ =4
  • y₂ = 3

Substitute the values into the formula.


m= (3 --2)/(4-3)

Solve the numerator.

  • 3 --2 = 3+2 = 5


m= (5)/(4-3)

Solve the denominator.


m= (5)/(1)=5

The slope of the line is 5.

User Sigalor
by
3.0k points