Question

Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).​

Answer 1

y = -2x + 16.

Explanation:

We are given the slope and a point on the line, so

we use the point-slope form of a straight line:

y - y1 = m(x - x1)

Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:

y - 8 = -2(x - 4)

y - 8 = -2x + 8

y = -2x + 16.