Answer:d
X^2+3\(x-1)x-3)
Explanation:
On Plato
Answer:
= x^2 + 3 / (x-1)(x-3)
Adjust fractions based on the LCM:
= (x-3)^2 / (x-1)(x-3) + 6(x-1) / (x-3) (x-1)
Combine the fractions (equal denominators):
= (x-3)^2 + 6(x-1) / (x-1) (x-3)
Expand:
x^2 + 3 / (x-1)(x-3)
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