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How much work is done if you lift a 12N object 5 meters? If that work is done in 6 seconds, how much power is exerted?

User Xiaoli
by
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1 Answer

3 votes

Answer:

mass=12N

distance=5

time taken=6 seconds

Now,

work done= f×d

= m×a×d. (:• f=m×a)

=12×10×5

= 600joule

again,.

power=w/t

= 600/6

=100 watt

User Jehiah
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4.8k points