229k views
4 votes
Find the sum of the first 9 terms in the following geometric series. 64+32+16+

User Cakraww
by
5.1k points

2 Answers

2 votes

Answer:

127.75

Explanation:

User Cal Courtney
by
5.6k points
3 votes

Answer:

The sum of the first 9 terms in the geometric series is 127.75

Explanation:

In the geometric series, there is a constant ratio between each two consecutive numbers

Examples:

5, 10, 20, 40, 80, ………………………. (×2)

5000, 1000, 200, 40, …………………………(÷5)

General term (nth term) of a Geometric series is

a1 = a, a2 = ar, a3 = ar², a4 = ar³, ..........


an=ar^(n-1), where

a is the first term

r is the constant ratio between each two consecutive terms

The sum of the first n terms of a Geometric series is calculated by this rule


Sn=(a(1-r^(n)))/(1-r)

Let us solve the question

∵ The geometric series is 64, 32, 16, .......................

a = 64

r = 32 ÷ 64 = 0.5

→ We need to find the sum of the first 9 terms

n = 9

→ Substitute these values on the formula of the sum above


S9=(64(1-0.5^(9)))/(1-0.5)

→ use the calculator to find the answer

S9 = 127.75

The sum of the first 9 terms in the geometric series is 127.75

User Martin Eden
by
5.3k points