Question

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.

2C8H18+25O2⟶16CO2+18H2O

How many moles of CO2 are emitted into the atmosphere when 16.1 g C8H18 is burned?

NEED ASAP PLEASE.

Answer 1

When 16.1 g of octane burn 1.12 moles of CO₂ are emitted in atmosphere.

Step-by-step explanation:

Given data:

Mass of octane C₈H₁₈ = 16.1 g

Moles of CO₂ emitted = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂ → 16CO₂+ 18H₂O

Number of moles of octane:

Number of moles = mass/molar mass

Number of moles = 16.1 g/ 114.23 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of octane with carbon dioxide.

C₈H₁₈ : CO₂

2 : 16

0.14 : 16/2×0.14 = 1.12 moles

When 16.1 g of octane burn 1.12 moles of CO₂ are emitted in atmosphere.