Question

What is the equation of a line that is parallel to the line y = 5x – 1 and passes

through the point (4, –3)?

Answer 1

y = 5x - 23

Explanation:

Since that is ll to y = 5x - 1, slope must be same as that of y = 5y - 1.

Compare y = 5y - 1 with y = mx + c, where m is slope.

Slope of the required line = 5.

And a point lying on that line is (4,-3). Therefore,

Equation is:

=> y - (-3) = 5(x - 4)

=> y + 3 = 5x - 20

=> y = 5x - 23