Question

James walks 2m north,5m south,5m east,and 3m north. What is the total magnitude of his displacement?

Answer 1

Magnitude of net displacement = 5m

Step-by-step explanation:

Let north = N, &

south = opposite to N = - N

Similarly, let east = E.

Now, add,

=> 2m north,5m south,5m east,and 3m north

=> 2N + 5(-N) + 5E + 3N

=> 2N - 5N + 5E + 3N

=> 5N - 5N + 5E

=> 5E => 5m east