Question

2. What volume will 3.00 moles of nitrogen gas occupy at STP?

Answer 1

Answer: V=67.2 L

Step-by-step explanation:

Ideal Gas Law: PV=nRT

P=1.00 atm (STP)

V=?

n=3.00 mol

R=0.08206Latm/Kmol

T=273.15 K (STP)

To find V, we would manipulate the equation to V=nRT/P

With significan figures, our answer is V=67.2 L.