Question

When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal piece, B, was immersed in 38.0 mL of water, the level of water rose to 60.0 mL. Compare the density of the metal pieces. A and B. Show your work.

Answer 1

A is denser than B as it's volume for the same mass is smaller.

Step-by-step explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

`V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL`

Next, we compute the densities as shown below:

`\rho_A=(m_A)/(V_A)=(5.00g)/(12.0mL)=0.42g/mL\\ \\\rho_B=(m_B)/(V_B)=(5.00g)/(22.0mL)=0.23g/mL`

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.