95.6k views
4 votes
If f(x)=x^3-4x^2-25x+28f(x)=x 3 −4x 2 −25x+28 and x-7x−7 is a factor of f(x)f(x), then find all of the zeros of f(x)f(x) algebraically.

User Henny
by
7.5k points

1 Answer

5 votes

9514 1404 393

Answer:

x = {7, 1, -4}

Explanation:

Dividing the given factor from the polynomial using synthetic division, we get ...

f(x) = (x -7)(x^2 +3x -4)

Factoring the quadratic* gives ...

f(x) = (x -7)(x -1)(x +4)

The zeros are the values of x that make these factors be zero:

x = {7, 1, -4}

_____

* The constants in the binomial factors are factors of -4 that have a sum of +3. Those are (-1)(4) = -4. -1+4 = 3.

If f(x)=x^3-4x^2-25x+28f(x)=x 3 −4x 2 −25x+28 and x-7x−7 is a factor of f(x)f(x), then-example-1
User Titania
by
7.1k points