Question

A football player threw a ball upward at an angle or 24 degrees with the horizontal with A velocity of 18 m/s. What are the vertical and horizontal components of the ball’s velocity?

Answer 1

`V_y = 16.44\ m/s`

`V_y = 7.32\ m/s`

Step-by-step explanation:

Given

`\theta = 24`

`Velocity\ (V) = 18m/s`

Required

Determine the vertical and horizontal components

The vertical (Vy) and horizontal (Vx) components is calculated as thus:

`V_x = Vcos\theta`

`V_y = Vsin\theta`

Calculating Vertical Components:

`V_y = Vsin\theta`

`V_y = 18 * sin24`

`V_y = 18 * 0.40673664307`

`V_y = 7.32125957526`

`V_y = 7.32\ m/s` --- Approximated

Calculating Horizontal Components:

`V_x = Vcos\theta`

`V_x = 18 * cos24`

`V_x = 18 * 0.91354545764`

`V_x = 16.4438182375`

`V_x = 16.44\ m/s` --- Approximated