166k views
2 votes
9A. A sample of hydrogen at 1.56 atm had it's pressure decreased to 0.73

atm producing a new volume of 751 mL. What was its original volume? *

User SeyT
by
8.2k points

1 Answer

2 votes

Answer:

351.43mL

Step-by-step explanation:

To calculate the original volume of hydrogen gas in this question, the Boyle's law equation will be used. Boyle's law equation is:

P1V1 = P2V2

Where; P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

According to this question, the P1= 1.56atm, V1 = ?, P2 = 0.73atm, V2 = 751mL

Hence;

P1V1 = P2V2

1.56 × V1 = 0.73 × 751

1.56 V1 = 548.23

V1 = 548.23/1.56

V1 = 351.43mL

Therefore, the original volume of hydrogen gas is 351.43 mL.

User Jonathan Wood
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.