Question

An object weighing 6 kg moving at a speed of 12 m / s was stopped by a force of 18 newton. At what time does the subject accelerate?​

Answer 1

F ΔT = Δ(M V)

Change in momentum is equal to applied force* time

Δ(M V) = 6 kg * 12 m / s = 72 kg-m / s

ΔT = 72 kg-m/s / 18 kg-m/s^2 = 6 s after 6 sec it will tend to rebound