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what is the equation of a line parallel to y=3x-2 and goes through the point (-1,1)

1 Answer

3 votes

Answer:

y = 3 x − 29

Explanation:

First, let's find the slope of the line

y = 3 x + 2

As the equation is already in slope-intercept form

y = m x + c

Slope = 3

Let a point ( x , y ) be on the new line.

By finding the slope again,

y − 1 x − 10 = 3

y − 1 = 3 ( x − 10 )

y − 1 = 3 x − 30

Which can then be converted to different forms:

Standard form:

3 x − y = 29

Equation form:

3 x − y−29 = 0

Slope-intercept form:

y = 3 x − 29

graph{3x-y=29 [-32.3, 47.7, -34.1, 5.9]}

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