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If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.

If the first number is reduced by 5 and the second number is increased 2 times, the difference between the second and first number is 9.
Find these numbers.

User Caltrop
by
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1 Answer

8 votes

Answer:

First number = 20

Second number = 12

Step-by-step explanation:

Let the 1st number be x

Let the 2nd number be y

=====================

Condition 1


\sf \rightarrow x + 7 + (y)/(6) = 29


\rightarrow \sf x=-(y)/(6)+22

=====================

Condition 2


\rightarrow \sf 2y - (x - 5) = 9


\rightarrow \sf x = 2y -4

=====================

Substitute equations


\rightarrow \sf -(y)/(6)+22 = 2y-4


\rightarrow \sf y=12

=====================

Find value of 1st number


\rightarrow \sf x = 2y - 4


\sf \rightarrow x = 2(12) - 4


\rightarrow \sf x = 20

User KeithWM
by
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