Question

If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.

If the first number is reduced by 5 and the second number is increased 2 times, the difference between the second and first number is 9.
Find these numbers.

Answer 1

First number = 20

Second number = 12

Step-by-step explanation:

Let the 1st number be x

Let the 2nd number be y

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Condition 1

`\sf \rightarrow x + 7 + (y)/(6) = 29`

`\rightarrow \sf x=-(y)/(6)+22`

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Condition 2

`\rightarrow \sf 2y - (x - 5) = 9`

`\rightarrow \sf x = 2y -4`

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Substitute equations

`\rightarrow \sf -(y)/(6)+22 = 2y-4`

`\rightarrow \sf y=12`

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Find value of 1st number

`\rightarrow \sf x = 2y - 4`

`\sf \rightarrow x = 2(12) - 4`

`\rightarrow \sf x = 20`