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What is the equation in slope-intercept form of the line that passes through the points (−12, −4) and (4, 8)?

A. y = −43 − 20
A. , y = −43 − 20

B. y = 43 − 12
B. , y = 43 − 12

C. y = −0.75 − 13
C. , y = −0.75 − 13

D. y = 0.75x +5
D. , y = 0.75x +5

User AxelWass
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1 Answer

5 votes

Answer:

Choice D.
y = 0.75\, x + 5.

Explanation:

The general equation for the slope-intercept form of a line in a cartesian plane is
y = m\, x + b, where:


  • m is the slope of the line, and

  • b is the
    y-intercept of the line. (The
    y\!-intercept of a line in a cartesian plane is the
    y\!\!-coordinate of the point where the line intersects the
    \! y \!-axis.)

Start by finding the value of
m. The slope of a line is equal to its rise-over-run. For the two points in this question:

  • The "rise" is the
    y-coordinate of the first point minus that of the second:
    \text{rise} = (-4) - 8 = -12.
  • The "run" is the
    x-coordinate of the first point minus that of the second. The order of these two points should stay the same:
    \text{run} = (-12) - 4 = -16.

Calculate the slope of this line:


\displaystyle m = \text{slope} = \frac{\text{rise}}{\text{run}} = (-12)/(-16) = 0.75.

The equation of the line becomes:


y = \underbrace{0.75}_(m)\, x + b.

Substitute the coordinates of either of the two points to find
b. For example, for the first point
(12, -4), substitute in the following:


  • x = -12, and

  • y = -4.

The equation becomes:


-4 = 0.75 * (-12) + b.

Solve for the value of
b:


b = 5.

Hence, the slope-intercept form of this line shall be:


y = 0.75\, x + 5.

User Hilnius
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