Question

What is the mass of Al₂O3 that will contain 10 kg of aluminium?​

Answer 1

108

Step-by-step explanation:

Molar mass of Al2O3 = (27 × 2) + (16 × 3)

= 54 + 48 = 102 g/mol

Moles in 204 g of Al2O3 = 204 g/(102 g/mol)

2 mol

Mass of aluminum in 1 mol of Al2O3 = 27 g × 2

= 54 g

Mass of aluminum in 2 mol of Al2O3 = 54 g × 2

= 108 g

Answer 2

1 mole of Al2O3 = 102 grams

1 mole of Al2 = 54 grams

102 grams of Al2O3 contains = 54 gram of Al2

10kg of Al2O3 contains = (54/102)*10000g Al2

= 5294.11 g Al2 or 5.29411 kg