Question

The Intensity level of a loud saw is 100 db at a distance of 5m. At what distance would the level be 80 db

Answer 1

50 m

Step-by-step explanation:

The relationship between the intensity of sound in dB and distance is given by the formula:

`B_2=B_1+20log((R_1)/(R_2) )\\\\Where \ B_2\ is \ the\ sound\ intensity\ at\ distance\ R_2\ and\\B_1\ is \ the\ sound\ intensity\ at\ distance\ R_1\ \\\\Given\ that: B_1=100\ dB, R_1=5\ m, B_2=80\ dB\\\\B_2=B_1+20log((R_1)/(R_2) )\\\\80=100+20log((5)/(R_2) )\\\\-20=20log((5)/(R_2) )\\\\log((5)/(R_2) )=-1\\\\(5)/(R_2)=10^(-1)\\\\(5)/(R_2)=0.1\\\\R_2=5/0.1=50\ m`