Question

Find the vertex and the axis of symmetry of the graph of the function
f(x)=3(x+1)^2

Answer 1

Answer: vertex (-1, 0) axis of symmetry -> x = -1

Explanation:

f(x) =
`3(x+1)^(2)`

to find the vertex do

x+1 = 0

to find the x value

x = -1

plug -1 into the equation

f(-1) =
`3(-1+1)^(2)`

f(-1) = 3(0)

f(-1) = 0

Therefore, the vertex is (-1, 0)

The axis of symmetry is

x = -1

because that is where the lowest x value is