1. How many grams of NaCl are required to prepare 3.5 L of 2.50 % (w/v) sodium chloride solution? A. 87.5 g B. 0.71 g C. 12.5 g D. 62.5 g

asked Jun 6, 2023 42.0k views

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4 votes

Answer:

87.5

Step-by-step explanation:

3.5 L to g would be 3500

3500*2.5%= 87.5 g

MLeblanc answered Jun 11, 2023

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