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factories by using middle term spitting x square +10x+21 (b) a square +8a+16 (c) p square -10p +25 (d) y square -7y+12​

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\bold{\huge{\underline{ Solution }}}

• Quadratic equation is defined as the equation having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c

• Generally, we solve quadratic equations by factorization method but it not applicable for two quadratic equations.

Factorization method is also applicable for linear, cubic etc.

• When we have two different types of quadratic equations then we use substitution method, elimination method and cross multiplication method.

• Factorization method is also known as middle term splitting method.

Let's come to the solution now,

Solution 1 :-

Here, we have equation


  • \sf{ x^(2) + 10x + 21 }

By using factorisation method


  • \sf{ x^(2) + 3x + 7x + 21 }

[ Here, we have taken 3 and 7 because "7 + 3 = 10 " and " 7 × 3 = 21 ]


\sf{ x( x + 3) + 7( x + 3 )}


\sf{ ( x + 3 ) ( x + 7) }

Hence, The required answer is

(x + 3)(x + 7) .

Solution 2 :-

Here ,we have equation


  • \sf{ a^(2) + 8a + 16 }

By using factorisation method,


  • \sf{ a^(2) + 4a + 4a + 16 }

[ Here, we have taken 4 and 4 because "4 + 4 = 8 " and " 4 × 4 = 16 ]


\sf{ a( a + 4) + 4( a + 4) }


\sf{ ( a + 4) ( a + 4) }

Hence, The required answer is

( a + 4)( a + 4) .

Solution 3 :-

Here, we have equation ,


  • \sf{ p^(2) - 10p + 25 }

By using factorisation method,


  • \sf{ p^(2) - 5p - 5p + 25 }

[ Here, we have taken - 5 and -5 because "-5 + (-5) = -5 - 5 = - 10 " and " -5 × -5 = 25]


\sf{ p( p - 5) - 5(p - 5) }


\sf{ ( p - 5) (p - 5) }

Hence, The required answer is

(p - 5)( p - 5) .

Solution 4 :-

Here, we have equation


  • \sf{ y^(2) - 7y + 12 }

By using factorisation method ,


  • \sf{ y^(2) - 4y - 3y + 12 }

[ Here, we have taken -4 and -3 because "- 4 + (- 3) = -4 - 3 = - 7 " and " -4 × -3 = 12]


\sf{ y( y - 4 ) - 3 ( y - 4 ) }


\sf{ ( y - 3) ( y - 4) }

Hence, The required answer is

(y - 3)( y - 4) .

User Jeferson Tenorio
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