Question

A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

Answer 1

`W=-6.99kJ`

Step-by-step explanation:

Hello,

In this case, since the work at constant pressure is computed via:

`W=P\Delta V=P(V_2-V_1)`

For an initial volume of 99.0 L and a final one of 98.0 L, accounting for a compression process at a pressure of 69.0 atm, we obtain a negative work, meaning that work is done on the gas, according to the first law of thermodynamics:

`W=69.0atm(98.0L-99.0L)\\\\W=-69atm*L`

However, the work in kJ with three significant figures because the initial data have all three significant figures, is:

`W=-69.0atm*L*(101.325kPa)/(1atm)*(1m^3)/(1000L) \\\\W=-6.99kJ`

Best regards.