Complete Question
According to a survey, 74% of households said that they have never purchased organic fruits or vegetables. Suppose that this result is true for the current population of households. a. Let x be a binomial random variable that denotes the number of households in a random sample of 10 who have never purchased organic fruits or vegetables. What are the possible values that x can assume? Integers to . b. Find to 3 decimal places the probability that exactly 6 households in a random sample of 10 will say that they have never purchased organic fruits or vegetables. Use the binomial probability distribution formula. Probability
Answer:
a
The possible value of x is 0, 1 ,2,3,4,5,6,7,8,9,10
b
![P(X = 6) = 0.158](https://img.qammunity.org/2021/formulas/mathematics/college/4ubf1tm865rd545lcaerecu5ho7q96lej7.png)
Explanation:
From the question we are told that
The proportion that stated that they have not purchased organic fruits or vegetables is
![p =0.74](https://img.qammunity.org/2021/formulas/mathematics/college/k8frjf8f3px5gzhb5hh4jfx87m6mn6qpcd.png)
The sample size is n = 10
The possible value x can take is 0, 1 ,2,3,4,5,6,7,8,9,10
Generally the probability that exactly 6 households in a random sample of 10 will say that they have never purchased organic fruits or vegetables is mathematically represented as
![P(X = 6) = ^nC_6 * p^(6)* (1-p)^(n-6)](https://img.qammunity.org/2021/formulas/mathematics/college/f1fiqz47gabhyjc9tlamctyp8pguy1hd4f.png)
Here C denotes combination
So
![P(X = 6) = ^(10)6 * (0.74)^(6)* (1-0.74)^(10-6)](https://img.qammunity.org/2021/formulas/mathematics/college/fl0u7usdkq1fbisg1r181snoftwz49pws8.png)
=>
![P(X = 6) = 0.158](https://img.qammunity.org/2021/formulas/mathematics/college/4ubf1tm865rd545lcaerecu5ho7q96lej7.png)