Question

A stone which is dropped into a dry well hits the bottom in 2.2s how deep is the well. take g=10m/s​

Answer 1

23.7m

Explanation:

Given parameters:

Time taken = 2.2s

Acceleration due to gravity = 10m/s

Unknown:

Depth of the well = ?

Solution:

To solve this problem, we simply apply one of the motion equations;

S = ut +
`(1)/(2)` gt²

where S = depth of the well

u = initial velocity

t = time taken

g = acceleration due to gravity

Input the parameters and solve for S;

Note initial velocity = 0;

S =
`(1)/(2)` x 9.8 x 2.2²

S = 23.7m