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A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank cost today if the power–sizing exponent is 0.57 and the construction cost index for such facilities has increased from 180 to 600 over the last 15 years? Choose the closest value.

1 Answer

5 votes

Answer:

The value is
P_o = \$ 561958.9

Explanation:

From the question we are told that

The capacity of the metal tank is
C =  2000 \  gallon

The duration usage is
t = 15\ years \ ago

The cost of 2000-gallon tank 15 years ago is
P =  \$100,000

The capacity of the second tank considered is
C_1 = 5,000

The power sizing exponent is
e = 0.57

The initial construction cost index is
u_1 = 180

The new construction after 15 years cost index is
u_2 =600

Equation for the power sizing exponent is mathematically represented as


(P_n)/(P) = [(C_1)/(C) ]^(e)

=> Here
P_n is the cost of 5,000-gallon tank as at 15 years ago

So


P_n  =  [(5000)/(2000) ] ^(0.57) * 100000


P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as


(P_o)/(P_n)  =  (u_2)/(u_1)

Here
P_o is the cost of 5,000-gallon tank today

So


(P_o)/(168587.7)  =  (600)/(180)

=>
P_o = (600)/(180) * 168587.7

=>
P_o = \$ 561958.9

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