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An amphitheater charges $74 for each seat in Section A, $59 for each seat in Section B, and $28 for each lawn seat. There are three times as many seats in Section B as in Section A. The revenue from selling all 13,000 seats is $503,000. Let x be the number of seats in A, y be the number of seats in B, and z be the number of lawn seats. Which system of equations represents the situation?

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Answer:

(4x+z)=13000------1

(4x+z)13000=503000----2

Explanation:

let x be the number of seats in A,

y be the number of seats in B, and

z be the number of lawn seats.

y=3x

the total number of seats is given by

(x+y+z)=13000

put y=3x

(x+3x+z)=13000

(4x+z)=13000------1

also

(4x+z)13000=503000----2

hence the systems of equation is

(4x+z)=13000------1

(4x+z)13000=503000----2

User Joran Den Houting
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