Question

Dairy Delight offers a free ice cream every time that the saleperson does not greet the customer with a smile. Last year Dairy Delight gave away free ice cream 3.8% of the time. What is the probability of randomly selecting 3 customers from last year who all received a free ice cream? Round the answer to 6 decimals. Show your work below.

Answer 1

The probability of randomly selecting 3 customers from last year who all received a free ice cream is 0.000054872.

Step-by-step explanation:

To find the probability of randomly selecting 3 customers who all received a free ice cream, we need to calculate the probability of one customer receiving a free ice cream and then apply the probability rule of independent events. Since Dairy Delight gave away free ice cream 3.8% of the time, the probability of a customer receiving a free ice cream on any given visit is 0.038. Assuming each customer visit is independent, we can calculate the probability of all 3 customers receiving a free ice cream by multiplying the individual probabilities together. Therefore, the probability of randomly selecting 3 customers who all received a free ice cream is 0.038 * 0.038 * 0.038 = 0.000054872.

Answer 2

0.000055

Step-by-step explanation:

Given that:

Percentage of free ice cream Given last year = 3.8%

From a total population of 1 ; proportion of those who received free ice cream = 3.8/100 = 0.038

Hence,

Probability of selecting a customer who received free Ice cream = 0.038

Hence, if 3 people are picked randomly from last year who received free ice cream:

(0.038 * 0.038 * 0.038) = 0.000054872

= 0.000055 ( to 6 decimal places)