Question

A 55 kg boy is throwing a 0.23 kg baseball up in the air. He decides to see how high he can throw it and uses a timer to see how long the ball stays in the air. He throws the ball as hard as he can straight up in the air and finds that it takes 5.5 seconds to come back to him. How long did it take for the ball to reach its highest point? (half the time it was in the air)

Answer 1

2.75 s

Step-by-step explanation:

From the question given above,

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

Thus, we can obtain the time taken (t) for the ball to reach the greatest height as follow:

T = 2t

Where:

T is the total time spent by the ball in air.

t is the time taken to reach the greatest height

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

T = 2t

5.5 = 2 × t

Divide both side by 2

t = 5.5/2

t = 2.75 s

Therefore, the time taken (t) to reach the greatest height is 2.75 s.