Question

A business knew that 30%, percent of its customers were less than 25 years old. The business wanted to increase this percentage, so they created a marketing campaign that targeted this age group. After the campaign, the business obtained a random sample of 50 customers to test H_o:p=0.3 versus ​Ha :p > 0.3, where p is the proportion of this business's customers who are less than 25 years old after the marketing campaign. After the campaign, the business obtained a random sample of 50 customers and found that 18 of those sampled were less than 25 years old. What would be the P-value for their test?

Answer 1

Explanation:

Answer 2

The answer is "0.9258201 or
`\bold{ \frac{0.36 -0.3}{\sqrt{(0.3 * 0.7 )/(50)}}}`".

Explanation:

`\to P= 30 \ \%\\\\ \to x= 18 \\\\ \to n=50\\\\\\\hat p= (x)/(n) = (18)/(50) = 0.36 \\\\\bold{Formula:}\\\\X= \frac{\hat p -p}{\sqrt{(p * (1-p))/(n)}}\\\\`

`= \frac{0.36 -0.3}{\sqrt{(0.3 * (1-0.3))/(50)}}\\\\= \frac{0.36 -0.3}{\sqrt{(0.3 * 0.7 )/(50)}}\\\\= \frac{0.36 -0.3}{\sqrt{(0.21)/(50)}}\\\\= (0.06)/(√(0.0042))\\\\= (0.06)/(0.064807407)\\\\= 0.9258201`