219k views
2 votes
In American football, the ball is punted by dropping and kicking it before it hits the ground. The height ht of the football above the ground in meters t seconds after being punted is affected by gravity and by the punter's kick, and can be represented as the difference of two functions: at=4.9t2, which specifies the effect of gravity on the height of the ball, and vt=13.7t+0.5, which specifies the effect of the punt on the ball. With these two functions, ht=vt-at, how high above the ground was the ball when it was punted?

1 Answer

3 votes

Answer:

The ball was 0.5 m above the ground before it was punted.

Explanation:

Since at = 4.9t² specifies the effect of gravity on the height of the ball, and vt = 13.7t + 0.5 specifies the effect of the punt on the ball, the height ht of the ball above the ground after the punt is ht=vt-at

ht = 13.7t + 0.5 - 4.9t². To find the height ht above the ground at which the ball was punted, we insert t = 0 which is the start time of the punt into the equation for ht. So with t = 0, ht becomes

ht = 13.7t + 0.5 - 4.9t²

ht = 13.7 × 0 + 0.5 - 4.9 × 0²

ht = 0 + 0.5 - 0

ht = 0.5 m

So the ball was 0.5 m above the ground before it was punted.

User Andrey Langovoy
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories