Question

4.2.32

Richard and Teo have a combined age of 41. Richard is 5 years older than twice Teo's age. How old are Richard and Teo?
Richard is years did, and Teo is years old.
Type whole numbers.)

Answer 1

Richard is 29 and Teo is 12

Explanation:

let Teo's age be n then Richard is 2n + 5 ( 5 more than twice Teo's age )

Thus their combined ages are

n + 2n + 5 = 41 , that is

3n + 5 = 41 ( subtract 5 from both sides )

3n = 36 ( divide both sides by 3 )

n = 12

Then

Teo is 12 years old and Richard is 2(12) + 5 = 24 + 5 = 29 years old

Answer 2

Explanation:

Let R = Richard, T = Teo.

Richard and Teo have a combined age of 41. This means that if you add their ages together you get 41:

R + T = 41

We are also told Richard is 5 years older than twice Teo's age:

R = 2T + 5

You can substitute " R " into R + T = 41

R + T = 41

2T + 5 + T = 41

3T + 5 = 41

Subtract 5 from both sides

3T = 41 - 5

3T = 36

Divide both sides by 3 to find T.

T = 36/3 = 12

We know that R + T = 41, so

R = 41 - T

R = 41 - 12

R = 29