Question 1

How to prove the vertical Angles Theorem

Question 2

Explanation:

$\underline{\bf{Given\::}} Given: \underline{\bf{To\:find\::}} Tofind: \underline{\bf{Explanation\::}} Explanation: \boxed{\bf{(1)/(f) =(1)/(v) -(1)/(u) }}}}\begin{gathered}\longrightarrow\sf{(1)/(-10) =(1)/(v) -(1)/(-30) }\\\\\\\longrightarrow\sf{(1)/(v) =(1)/(-10) +(1)/(30) }\\\\\\\longrightarrow\sf{(1)/(v) =(-3+1)/(30) }\\\\\\\longrightarrow\sf{(1)/(v) =\cancel{(-2)/(30) }}\\\\\\\longrightarrow\sf{(1)/(v) =(1)/(-15) }\\\\\\\longrightarrow\sf{v=-15\:cm}\end{gathered} ⟶ −101 = v1 − −301 ⟶ v1 = −101 + 301 ⟶ v1 = 30−3+1 ⟶ v1 = 30−2 ⟶ v1 = −151 ⟶v=−15cm \boxed{\bf{M \:A \:G \:N\: I \:F \:I \:C\: A\: T \:I \:O\: N :}} MAGNIFICATION: \begin{gathered}\mapsto\sf{m=(Height\:of\:image\:(I))/(Height\:of\:object\:(O)) =(Distance\:of\:image)/(Distance\:of\:object) =(v)/(u) }\\\\\\\mapsto\sf{m=\cancel{(-30)/(-15)} }\\\\\\\mapsto\bf{m=2\:cm}\end{gathered} ↦m= Heightofobject(O)Heightofimage(I) = DistanceofobjectDistanceofimage = uv ↦m= −15−30 ↦m=2cm Thus;The magnification will be 2 cm .$

Question 3

Answer:

see below

Explanation:

Angles opposite each other when two lines cross. (see attached)

in the attached example, the angle a° and b° are vertical angles.

How to prove the vertical Angles Theorem-example-1

Ryan Le · Answer 1 · 2021-11-19T23:33:48+0000

Answer:

see below

Explanation:

Angles opposite each other when two lines cross. (see attached)

in the attached example, the angle a° and b° are vertical angles.

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions