Question

Can you help me to solve this​

Answer 1

Answer: 4a-2/2a+1
Explanation: first factor out the expression. Second cancel out

Answer 2

`(4a-2)/(2a+1)`

Explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

`(8a^2-2)/(4a^2+4a+1)`

=
`(2(2a-1)(2a+1))/((2a+1)(2a+1))` ← cancel (2a + 1) on numerator/ denominator

=
`(2(2a-1))/(2a+1)`

=
`(4a-2)/(2a+1)`