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An unknown substance weighing 50.0g was heated from 36.0 to 69.0. In this process, the substance absorbed 5890.0J of energy. What is the specific heat of the substance

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I am assuming that the temperature given is in Celsius. In order to solve for the heat capacity, use q = mc△T. Your q = -5890.0J, m = 50.0 g, and △T 33.0 °C (69.0 - 36.0). Use algebra to solve for your heat capacity (c). Remember, heat capacity is measured in joules per gram Celsius (J/g °C), and don’t forget your significant figures.
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