Question

A vendor at a craft show sold items for $4.50, $6.00, and $7.50.

Altogether, the vendor sold 87 items for a total of $489. The vendor
sold five more items for $6.00 than for $7.50.

Let x = number of $4.50 craft items sold
Let y = number of $6.00 craft items sold
Let z = number of $7.50 craft items sold

Which system of equations could you use to determine how many
of each item were sold?


x + y + z = 489
z = y + 5
4.5x + 6y + 7.5z = 87

x + y + z = 87
y = z + 5
4.5x + 6y + 7.5z = 489

x + y + z = 489
y = z + 5
4.5x + 6y + 7.5z = 87

x + y + z = 87
z = y + 5
4.5x + 6y + 7.5z = 489

Answer 1

Explanation:

its 20 25 42

Answer 2

You could either use the second or fourth system as each of these choices have x+y+z=87 in the first equation.

Explanation:

Answer(s) is above. Hope it helps!