Question

NO LINKS!! Please help me with this problem​

Answer 1

• Mix A is 2 units
• Mix B is 1 unit
• Mix C is 3 units

Explanation:

Let amount of Mix A is a, Mix B is b, Mix C is c.

With the given details, we get the following system

• 5a + 6b + 4c = 28
• 4a + 2b + c = 13
• 3a + 4b + 4c = 22

Find the value of c (the easiest one) for substitution

• c = 13 - 4a - b

Substitute c into the first equation

• 5a + 6b + 4(13 - 4a - 2b) = 28
• 5a + 6b + 52 - 16a - 8b = 28
• - 11a - 2b = 28 - 52
• 11a + 2b = 24 (5)

Substitute c into the third equation

• 3a + 4b + 4(13 - 4a - 2b) = 22
• 3a + 4b + 52 - 16a - 8b = 22
• - 13a - 4b = 22 - 52
• 13a + 4b = 30 (6)

Double the equation (5) and subtract (6), find the value of a

• 2(11a + 2b) - 13a - 4b = 2(24) - 30
• 22a - 13a = 48 - 30
• 9a = 18
• a = 2

Find b

• 11*2 + 2b = 24
• 22 + 2b = 24
• 2b = 2
• b = 1

Now find c

• c = 13 - 4*2 - 2*1
• c = 13 - 8 - 2
• c = 3