Question

8 You are given 20.00g of a dry mixture of sand and table salt.

After adding water and filtering, you are left with wet sand on
the filter paper. The filter paper and sand is then dried and the
mass of the dry sand alone is found to be 5.00g. What was the
% sand in the original mixture?

Answer 1

`\%sand=25\%`

Step-by-step explanation:

Hello.

In this case, given the mass of the mixture, we can define it in terms of the mass of sand and table salt as shown below:

`m_(sand)+m_(salt)=20.00g`

Moreover, as after filtering, the mass of dry sand turns out 5.00 g, we can compute the % sand in the original mixture by dividing this value over the mass of the mixture as shown below:

`\%sand=(m_(sand))/(m_(mixture))*100\%\\ \\\%sand=(5.00g)/(20.00g)* 100\%\\\\\%sand=25\%`

Best regards!