Answer:
The answer is
![\huge 7.40 * {10}^(21) Hz](https://img.qammunity.org/2021/formulas/chemistry/college/f6sbpb7cyfi7f11ylhgfhhiorsvt2qzwa5.png)
Step-by-step explanation:
To find the frequency of the wave we use the formula
![f = (E)/(h) \\](https://img.qammunity.org/2021/formulas/chemistry/college/zcec8b0erdcr695oknhx3o1ldgctndi3mx.png)
where
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question
E = 4.90 × 10-¹² J
So we have
![f = \frac{4.90 * {10}^( - 12) }{6.626 * {10}^( - 34) } \\](https://img.qammunity.org/2021/formulas/chemistry/college/pwi8c09f9h107gxavnvx8azu6wf7stekyo.png)
We have the final answer as
![7.40 * {10}^(21) \: \: Hz](https://img.qammunity.org/2021/formulas/chemistry/college/h0gau4jlw0e0citzvy5fq1266liq3es8zr.png)
Hope this helps you