Question

What is the pressure if the height of a column of mercury is 0.20 m and the density of mercury is 13,600 kg/m3? (remember, gravity is 9.81 m/s2)

Answer 1

`p=26683.2Pa`

Step-by-step explanation:

Hello,

In this case, since the pressure is computed via:

`p=h*\rho*g`

Whereas h is the 0.520-m height,
`\rho` is the 13600-kg/m³ density and the g the 9.81-m/s² gravity. Thus, the pressure in Pa is:

`p=0.20m*13,600 (kg)/(m^3) *9.81(m)/(s^2) \\\\p=26683.2(kg*(m)/(s^2) )/(m^2) =26683.2(N)/(m^2)\\ \\p=26683.2Pa`

Best regards.