Question

I need help! Find the equation of a line parallel to 3x-3y=5 that contains the point (-1,-5). Write the equation in slope Intercept form.

Answer 1

the equation of the line is y= x-4

Explanation:

so so the first thing that you're going to do is get y alone

-x-5=y

next you're going to find your slope which in this case is negative one.

after that in order to find the equation of a parallel line you're going to find the reciprocal of the slope.

so in this case the reciprocal is one.

next you're going to substitute in the cordinates to find the y intercept

x+b=y. (-1)+b= -5. (. b is the y intercept)

b= -4