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Given 9, 12, 15, 18, 21, 24 ... Write an algebraic representation for this sequence.

1 Answer

4 votes

Answer:

tn=9+3(n-1)

Explanation:

Formula: tn=t1+d(n-1)

AKA: term n=term 1 plus common difference times n minus 1

For this sequence: tn=tn; t1=9; common difference=3; n-1=n-1

Plug in the answer: tn=9+3(n-1)

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