Answer: Option A.
Spring B has a larger displacement that spring A.
Step-by-step explanation:
Spring B has a larger displacement that spring A .
By using Hooke's law.
F=-Kx
Where F is force, K is spring constant and x is displacement.
For spring a
Weight / force is 2 kg
Spring constant (K) is 5/nm
Therefore,
F=-Kx
2=-5x
X=2/-5
X= -0.4m
For spring B.
Weight is 10Kg
Spring constant is 9N/m
F=-Kx
10=-9x
X=-10/9
=-1.1m
Therefore Spring B have larger displacement than spring A.
In Hooke's law, negative sign that is present on the spring's force indicate that the force exerted by the spring opposes the spring's displacement.