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Make x the subject of y=alog(5x)

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Answer:

x = 0.2(10^y/a).

Explanation:

y = alog(5x)

y = log(5x)^a) By the definition of a log:

(5x)^a = 10^y

5x = (10^y) ^ 1/a

x = 0.2(10^y/a)

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