Question

What is the frequency of a photon of light (in Hz) that has an energy of 2.50 x 10-18 J?

Answer 1

The answer is

`3.77 * {10}^(15) \: \: \: Hz`

Step-by-step explanation:

The frequency of the photon can be found by using the formula

`f = (E)/(h) \\`

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

E = 2.50 × 10^-18 J

So we have

`f = \frac{2.50 * {10}^( - 18) }{6.626 * {10}^( - 34) } \\`

We have the final answer as

`3.77 * {10}^(15) \: \: \: Hz`

Hope this helps you