Question

What is the equation of the line that passes through the point (-8, 3) and has a
slope of -1/4

Answer 1

-1/4x + 1 ( If this is wrong then ignore this)

Explanation:

The formula for a problem like this is y - y1 = m(x - x1). The x coordinate, -8 is the x1 and the y coordinate 3 is x1. So the equation is y - 3 = -1/4(x + 8)

Equation:

y - 3 = -1/4(x + 8)

y - 3= -1/4x - 2

y = -1/4x + 1

Therefore the equation for the line is y = -1/4x + 1

Answer 2

Given parameters:

Slope of the line =
`-(1)/(4)`

Coordinates of the points = (-8, 3)

Unknown:

Equation of the line = ?

Solution:

To find the equation of the line, we must note that any straight line can be represented by the equation;

y = mx + c

where x and y are the coordinates

m is the slope

c is the y-intercept of the line

Input the parameters and solve for c;

x = -8 and y = 3;

3 =
`-(1)/(4)` x (-8) + c

3 = 2 + c

c = 1;

So the equation of the line is ;

y =
`-(1)/(4)`x + 1

multiply through by 4;

4y = -x + 4

The equation of the line is 4y = -x + 4