Answer:
12/5 hours
Explanation:
Let the total area to be painted be X
Let S be the rate at which Sally paints and J be the rate at which Joe paints
We have:
X/S = 4 hours (1)
X/J = 6 hours (2)
(1) ÷ (2) ==>
LHS = X/S ÷ X/j = X/S × J/X ==> J/S (3)
RHS = 4/6 = 2/3 (4)
From (3) and (4)
J/S = 2/3 or J =2/3 × S
If they both paint at the same time time taken is
X/(S+J)
S + J = S + 2/3 *S = 5/3S
So time taken for both of them to paint is X/(5/3)*S = X/S * 3/5
But we know from (1) that X/S = 4 so time taken = 4 * 3/5 = 12/5 hours