Question

JK has endpoints at J(6,-1) and K(-3,-4). If M is the midpoint of JK, approximately what is JM ?

Answer 1

midpoint of J and K = (3/2,-5/2) or (1.5,-2.5)

Explanation:

midpoint formula: (((x+x1)/2),((y+y1)/2)))

in this case J(x1,y1), and K(x,y) where J = (6,-1), and K = (-3,-4).

so: (((-3+6)/2),((-4+-1)/2))) = (((3)/2),((-5)/2))) = (1.5,-2.5) or (3/2,-5/2)